BucketSort(A) COST*TIMES n = length(A) 1 for i = 1 to n n+1 insert(A[i], B[floor(nA[i])] n for i = 0 to n-1 n+1 InsertionSort(B[i]) n*T(InsertionSort) return(B[0].B[1].....B[n-1]) n