Rank(T,x) ; return rank of node x 1 rank = size(left(x)) + 1 2 while x root(T) 3 if x = right(parent(x)) 4 then rank = rank + size(left(parent(x))) + 1 5 x = parent(x) 6 return rank
T(n) is approximately equal to height of tree = O(lg n)